Question

Four closed tanks, A, B, C, and D, each contain an ideal gas. The table gives the absolute pressure and volume of the gas in each tank. In each case, there is 0.14 mol of gas. Using this number and the data in the table, compute the temperature of the gas in each tank.

A B C D
Absolute pressure (Pa) 25.0 30.0 20.0 2.0
Volume (m³) 4.0 5.0 5.0 75

Answer 1

The temperature of the gas in each tank can be calculated using the ideal gas law equation, PV = nRT. Tank A has a temperature of 93.91 K, Tank B has a temperature of 107.51 K, Tank C has a temperature of 71.68 K, and Tank D has a temperature of 12.66 K.

Step-by-step explanation:

The temperature of a gas can be calculated using the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. To calculate the temperature, we can rearrange the equation to T = PV / (nR). Let's calculate the temperature for each tank:

Tank A: T = (25.0 Pa * 4.0 m³) / (0.14 mol * 8.314 J/(K·mol)) = 93.91 K

Tank B: T = (30.0 Pa * 5.0 m³) / (0.14 mol * 8.314 J/(K·mol)) = 107.51 K

Tank C: T = (20.0 Pa * 5.0 m³) / (0.14 mol * 8.314 J/(K·mol)) = 71.68 K

Tank D: T = (2.0 Pa * 75 m³) / (0.14 mol * 8.314 J/(K·mol)) = 12.66 K