Question

What are the solutions of the quadratic equation p^2+3p-28=40

Answer 1

`\bold{p_1\approx6.88\ ,\qquad p_2\approx-9.88}`

Explanation:

`p^2+3p-28=40\\\\p^2+3p-68=0\\\\a=1\,,\ b=3\,,\ c=-68\\\\\\p=(-3\pm√(3^2-4\cdot1\cdot(-68)))/(2\cdot1)=(-3\pm√(281))/(2)\\\\p_1\approx6.88\ ,\qquad p_2\approx-9.88`

Answer 2

the answer is =-3±
`√(281)`/2

Explanation: