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Use the function (f(x) = -16x^2 + 60x + 16) and completely factor (f(x)).

a. (-16(x+1)(x-1))
b. (-16(x+4)(x-1))
c. (-16(x-4)(x+1))
d. (-16(x-4)(x-1))

1 Answer

5 votes

Final answer:

The correct factored form of the quadratic function f(x) = -16x^2 + 60x + 16 is -16(x - 4)(x + 4), as it satisfies the condition of factoring a quadratic equation.

Step-by-step explanation:

To factor the quadratic function f(x) = -16x^2 + 60x + 16, we must find two binomials that multiply to give the original quadratic equation. We look for two numbers that multiply to give the product of the coefficient of x^2 (which is -16) and the constant term (which is +16), and add to give the coefficient of x (which is +60).

Upon inspection, we see that the numbers +64 and -4 satisfy these conditions because (64)(-4) = -256 and 64 - 4 = 60. So we can rewrite the quadratic equation as:

f(x) = -16(x - 4)(x + 4)

It's the distributive property in reverse, also called factoring. To check our work, we can distribute the binomials back out and confirm they give us our original equation.

answered
User Peter Jacoby
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