Question

What is the solution of (2i-j).(3i+k)​

a) 6i+2j−3k
b) 6i−2j−3k
c) 6i+2j+3k
d) −6i+2j+3k

Answer 1

The solution of the expression (2i-j)(3i+k) is -6 - 3ij + 2ik - jk.

Step-by-step explanation:

To find the solution of the expression (2i-j)(3i+k), we can use the distributive property of multiplication over addition. This means we distribute the first term in the first expression to every term in the second expression, and then distribute the second term in the first expression to every term in the second expression.

(2i-j)(3i+k) = 2i(3i+k) - j(3i+k)

= 6i^2 + 2ik - 3ij - jk

= -6 - 3ij + 2ik - jk

So, the solution is -6 - 3ij + 2ik - jk. Therefore, the correct answer is option d) -6i+2j+3k.