Question

If ( p ) and ( q ) are the zeros of the polynomial, then (-F(x) = 2x^2 - 7x + 3). Find the value of ( p^2 ) and ( q^2 ).

a) ( p^2 + q^2 = 49 )

b) ( p^2 times q^2 = 1 )

c) ( p^2 + q^2 = 25 )

d) ( p^2 times q^2 = 9 )

Answer 1

To find the values of p^2 and q^2 for the given polynomial, we need to first find the zeros of the polynomial. Then, we can simply square the values of p and q to find p^2 and q^2, respectively. In this case, the values of p^2 and q^2 are 1 and 2.25.

Step-by-step explanation:

To find the values of p^2 and q^2 for the polynomial -F(x) = 2x^2 - 7x + 3, we need to first find the zeros of the polynomial, which are p and q. The zeros can be found by setting the polynomial equal to zero and solving for x. In this case, we have 2x^2 - 7x + 3 = 0.

Using factoring or the quadratic formula, we can find that the zeros are p = 1 and q = 1.5. To find p^2, we can simply square the value of p: p^2 = 1^2 = 1. Similarly, q^2 = (1.5)^2 = 2.25.

So, the values of p^2 and q^2 are 1 and 2.25.