Question

20.00 mL aliquots of HCL with methyl orange as an indicator. Titers of 17.68, 17.73, 17.69 mL. Equation for the reaction:

2HCl + 2NaOH -> 2NaCl + 2H₂O
HCl + NaOH -> NaCl + H₂O
HCl + H₂O -> H₃O+ + Cl-
2HCl -> 2H+ + 2Cl-

Answer 1

Titration analysis of HCl with NaOH was conducted using methyl orange as an indicator.

Step-by-step explanation:

The question asks about titration analysis involving the reaction between HCl and NaOH. In a titration, a known volume of one solution of known concentration (the titrant) is reacted with a known volume of a solution of unknown concentration (the analyte).

In this case, the reaction is: HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l).

Based on the given information, it appears that three 20.00 mL aliquots of HCl were titrated using methyl orange as an indicator. The titers obtained were 17.68 mL, 17.73 mL, and 17.69 mL.