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Consider the densities (in kilograms per cubic meter) of the ten most abundant elements by weight in Earth's crust:

1.4, 2330, 2700, 7870, 1500, 970, 900, 1740, 4500, 0.09
Match each density value with the corresponding element.
A. 1.4
B. 2330
C. 2700
D. 7870
E. 1500
F. 970
G. 900
H. 1740
I. 4500
J. 0.09

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User Najmul
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1 Answer

5 votes

Final answer:

To match the densities to the elements in Earth's crust, we can relate the known physical properties of these elements such as being gaseous, lightweight, or heavy and dense, to the densities provided, among which Oxygen corresponds to 0.09 kg/m³, Aluminum to 2700 kg/m³, and Iron to 7870 kg/m³.

Step-by-step explanation:

Matching Densities to Earth's Crust Elements

The question involves matching the given densities in kilograms per cubic meter with the corresponding elements that are most abundant in Earth's crust. Since we are given the density values and know the most abundant elements, it is possible to map these densities to specific elements based on typical known values.

  • Oxygen (O) - Given its gaseous state, it would have a low density, corresponding to J. 0.09 kg/m³.
  • Aluminum (Al) - Known for being a lightweight metal, matches C. 2700 kg/m³.
  • Iron (Fe) - As a heavy and dense metal, fits D. 7870 kg/m³.

Other notable matches would be based on known densities of these elements, which would generally align with the given data. For example, silicon (Si) has a density closer to aluminum, magnesium is less dense than aluminum but heavier than many non-metals, calcium is lighter than iron but heavier than potassium and sodium, which are some of the lightest metals.

answered
User Greg Bacon
by
9.2k points
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