asked 226k views
2 votes
A diver springs upward with an initial speed of 1.8 m/s from a3.0-m board. Find thevelocity with which he strikes the water.

1 Answer

4 votes

Final answer:

Using a kinematic equation, we can calculate the velocity of a diver when he strikes the water. The initial upward velocity and the height of the diving board are used to determine that the diver's final velocity is approximately -7.67 m/s, with the negative sign indicating the downward direction.

Step-by-step explanation:

To find the velocity at which the diver strikes the water, we can use the following kinematic equation that relates initial velocity, acceleration, displacement, and final velocity:

v² = v₀² + 2a(y - y₀)

Where:

  • v is the final velocity
  • v₀ is the initial velocity (1.8 m/s)
  • a is the acceleration due to gravity (9.8 m/s²)
  • y - y₀ is the displacement (since the diver is returning to the original elevation of the pool's surface, this is the negative of the height of the board, -3.0m)

Plugging in the values, we get:

v² = (1.8 m/s)² + 2(9.8 m/s²)(-3.0 m)

v = sqrt((1.8 m/s)² - 2(9.8 m/s²)(3.0 m))

v ≈ -7.67 m/s

The negative sign indicates the direction of the velocity is downward, while the magnitude gives us the speed at which he strikes the water.

answered
User Chris Hughes
by
7.2k points