asked 101k views
1 vote
How many grams of NaCI per kilogram of water are present in a 2.7 molal aqueous solution​

asked
User Gjohn
by
8.4k points

1 Answer

6 votes

Answer:

157.79 g

Step-by-step explanation:

The definition of molality is:

  • molality = moles of solute / kilogram of solvent

This means that in a 2.7 molal solution, there are 2.7 moles of NaCl per kilogram of water.

So now we convert those 2.7 moles of NaCl to grams, using its molar mass:

  • 2.7 mol * 58.44 g/mol = 157.79 g
answered
User Wouter Vanherck
by
7.5k points
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