Final Answer:
The compound with the given molecular formula C₅H₁₀OC₅H₁₀O, proton-decoupled C¹³ NMR data (δ 14, 17, 30, 45, 207 ppm), and H¹ NMR spectral data (δ 0.9 (t, 3H), 1.60 (m, 5H), 2.10 (s, 3H), 2.40 (t, 2H), contains a ketone functional group and is identified as diethyl ketone (CH₃C(O)C₂H₅).
Step-by-step explanation:
The molecular formula, C₅H₁₀OC₅H₁₀O, indicates the presence of two identical groups, each with five carbon atoms and a single oxygen. Considering the proton-decoupled C¹³ NMR data, the signals at δ 14, 17, 30, and 45 ppm suggest the presence of methylene (CH₂) and methine (CH) carbons, while the signal at 207 ppm indicates a carbonyl carbon (C=O). These findings are consistent with the structure of a ketone.
The H¹ NMR spectral data further supports the identification. The peaks at δ 0.9 (t, 3H) and 2.40 (t, 2H) correspond to the methyl and methylene protons adjacent to the carbonyl group, respectively. The peak at 1.60 (m, 5H) corresponds to the protons in the alkyl group adjacent to the carbonyl, and the peak at 2.10 (s, 3H) corresponds to the methyl group directly bonded to oxygen in the ether moiety. These chemical shifts and coupling patterns align with the expected values for diethyl ketone.
In conclusion, the compound is diethyl ketone (CH₃C(O)C₂H₅), featuring a ketone functional group and consistent with the provided molecular formula and NMR data.