Final answer:
To express 13 as a linear combination of 1, 2b, and 5, we need to find values of b that satisfy the equation 1x + (2b)y + 5z = 13. The possible values of b are any integers that divide evenly into 13 - x - 5z.
Step-by-step explanation:
To express 13 as a linear combination of 1, 2b, and 5, we need to find values of b that satisfy the equation 1x + (2b)y + 5z = 13, where x, y, and z are integers.
Let's start by solving the equation for x, y, and z.
1x + (2b)y + 5z = 13
We can rearrange the equation to isolate y:
(2b)y = 13 - x - 5z
Dividing both sides of the equation by 2b, we get:
y = (13 - x - 5z) / 2b
In order for y to be an integer, 13 - x - 5z must be divisible by 2b.
This means that the possible values of b are any integers that divide evenly into 13 - x - 5z.