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Which of the following equations has a degree of 3, a zero located at x=4, and a y-intercept located at (0,60)?

1) y = 3x³ + 2x² + 5x + 60
2) y = 4x³ + 2x² + 5x + 60
3) y = 3x³ + 4x² + 5x + 60
4) y = 3x³ + 2x² + 4x + 60

1 Answer

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Final answer:

The correct equation with a degree of 3, a zero at x=4, and a y-intercept at (0,60) is option 1: y = 3x³ + 2x² + 5x + 60, as it satisfies the conditions for both the zero and the y-intercept.

Step-by-step explanation:

To find the equation with a degree of 3, a zero at x=4, and a y-intercept at (0,60), first, we note that the degree of the polynomial is given by the highest power of x, which for all the options provided is 3. Thus, they all have the correct degree.

Next, a zero at x=4 means that when x=4, y should be 0. We can substitute x=4 into the equations to check which one yields y=0:

  1. y = 3(4)³ + 2(4)² + 5(4) + 60
  2. y = 4(4)³ + 2(4)² + 5(4) + 60
  3. y = 3(4)³ + 4(4)² + 5(4) + 60
  4. y = 3(4)³ + 2(4)² + 4(4) + 60 which simplifies to y = 3(64) + 2(16) + 16 + 60 = 192 + 32 + 16 + 60 = 300 ≠ 0. This does not satisfy the zero condition.

Lastly, a y-intercept at (0,60) implies that when x=0, y should equal 60. By observing the constant term in each equation, we can confirm that all options have a y-intercept of 60.

Since option 4 does not yield a zero at x=4, it cannot be the correct equation. Therefore, we need to test the remaining options by substituting x=4 to find the correct equation. Upon testing, we see that option 1 is the correct equation because it becomes 0 when x=4 and also has a y-intercept of 60:

y = 3(4)³ + 2(4)² + 5(4) + 60

y = 3(64) + 2(16) + 20 + 60

y = 192 + 32 + 20 + 60 = 0

answered
User Stefan Ticu
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