Question

Find the z-score corresponding to an observation of 4.7 in a normal distribution with mean 5.7 and standard deviation 0.61.

Answer 1

The z-score corresponding to the observation of 4.7 in a normal distribution with mean 5.7 and standard deviation 0.61 is approximately -1.6393.

Step-by-step explanation:

To find the z-score corresponding to an observation of 4.7 in a normal distribution with mean 5.7 and standard deviation 0.61, we can use the formula:

z = (x - mean) / standard deviation

Substituting the values:

z = (4.7 - 5.7) / 0.61 = -1.6393

The z-score corresponding to the observation of 4.7 is approximately -1.6393.