Final answer:
To determine the current in the 3.00 Ω resistor, total resistance of the circuit is calculated by adding all resistances in series, then Ohm’s Law (I = V / R) is used with the total voltage to find the current, which remains the same through all resistors in a series circuit.
Step-by-step explanation:
To find the current in a 3.00 Ω resistor, we must first understand the configuration of the circuit. Given the information from different parts of the question, it seems we are dealing with a series circuit with a total voltage and several resistors with known resistances.
Firstly, we calculate the total resistance of the circuit using the formula for resistors in series, which is the sum of all individual resistances: Rs = R1 + R2 + R3.
Once we have the total resistance and the total voltage provided by the source, we can use Ohm's Law, which is I = V / R, to find the total current in the circuit. Since it's a series circuit, the current through each resistor, including the 3.00 Ω resistor, will be the same.
In one of the provided information snippets, the loop equation VIR1 - IR2 - IR3 = 0 could be a hint that we should apply Kirchhoff's voltage law, which, in a series circuit is typically simplified into the summation of voltage drops across individual resistors equalling the total voltage provided by the source.