Final answer:
The compound CH3-O-CH3 is correctly classified as an ether, which is characterized by an oxygen atom connected to two alkyl or aryl groups and does not have a hydroxyl or carbonyl group. so, option 2 is the correct answer.
Step-by-step explanation:
The correct classification of the compound CH3-O-CH3 is an ether. An ether is characterized by an oxygen atom connected to two alkyl or aryl groups with the general form R—O—R'. Alcohol, on the other hand, contains one or more hydroxyl (-OH) groups bonded to a carbon atom. The compound given does not have any hydroxyl group; thus, it is not an alcohol. Additionally, it does not contain the carbonyl group (C=O) required for it to be classified as an aldehyde or a ketone.
The compound CH₃-O-CH₃ is classified as an ether. It has the general formula R—O—R, where R represents any group.
The compound CH₃-O-CH₃ is classified as an ether. It has the general formula R—O—R, where R represents any group. In this case, both sides of the oxygen atom are methyl groups (CH₃), which makes it an ether.