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3 votes
a spherical balloon is to be deflated so that its radius decreases at a constant rate of 8 cm/min. at what rate must air be removed when the radius is 5 cm?

1 Answer

5 votes

Answer:

V = (4/3)πr³

dV/dt = 4πr²(dr/dt)

= 4π((5 cm)²)(-8 cm/min)

= -800π cm³/min

Air must be removed at the rate of 800π cm³/min.

answered
User Cobaco
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