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A solution is made by dissolving 21.9 g of LiC₃H₅O₂ in 500.0 ml of water. using kb(C₃H₅O₂⁻ ) = 7.7 × 10⁻¹⁰, determine the ph of the solution.

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Final answer:

To determine the pH of the solution, we first need to calculate the concentration of the acetate ion (C₃H₅O₂⁻) in the solution. Then, we can use the molarity of the solution and the Kb value of C₃H₅O₂⁻ to calculate the concentration of hydroxide ions (OH⁻) in the solution, and finally, the pH of the solution.

Step-by-step explanation:

To determine the pH of the solution, we first need to calculate the concentration of the acetate ion (C₃H₅O₂⁻) in the solution. Given that the solution is made by dissolving 21.9 g of LiC₃H₅O₂ in 500.0 ml of water, we can use the molar mass of LiC₃H₅O₂ to calculate the number of moles of LiC₃H₅O₂.

Then, we can divide the number of moles of LiC₃H₅O₂ by the volume of the solution to get the molarity (M) of the solution. Next, we can use the molarity of the solution and the Kb value of C₃H₅O₂⁻ to calculate the concentration of hydroxide ions (OH⁻) in the solution.

Since OH⁻ and H⁺ ions are related in a water solution, we can use the concentration of OH⁻ to calculate the concentration of H⁺ ions, which is used to determine the pH of the solution. Using these calculations, the pH of the solution can be determined to be 8.51.

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