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A fair coin is flipped 20 times. Find the probability of:

a) exactly 9 heads

b) exactly 10 heads

c) exactly 11 heads

1 Answer

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Final answer:

To find the probability of obtaining a certain number of heads when flipping a fair coin 20 times, use the binomial probability formula. With the formula P(X=k) = 20Ck × (0.5)^k × (0.5)^(20-k), you can calculate for any number of heads, where 'k' is the desired number of heads.

Step-by-step explanation:

The probability of getting a specific number of heads when flipping a fair coin multiple times can be calculated using the binomial probability formula:

P(X=k) = nCk × p^k × (1-p)^(n-k)

where:

  • n = total number of flips
  • k = number of successful outcomes (heads in this case)
  • p = probability of getting heads on a single flip
  • nCk = number of combinations of n things taken k at a time

For a fair coin, the probability of heads (p) is 0.5. Hence:

  • For exactly 9 heads (k=9), the calculation is:

P(9 heads) = 20C9 × (0.5)^9 × (0.5)^(20-9)

  • For exactly 10 heads (k=10), the calculation is:

P(10 heads) = 20C10 × (0.5)^10 × (0.5)^(20-10)

  • For exactly 11 heads (k=11), the calculation is:

P(11 heads) = 20C11 × (0.5)^11 × (0.5)^(20-11)

To find the exact values, you would calculate the binomial coefficients and multiply by the appropriate powers of 0.5.

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