Question

A physics teacher accelerated a 0.250 kg trolley from rest to a speed of 6.00m/s in a time of 0.200s. what was the average force that was applied to the trolley? (neglect friction)

Answer 1

The average force applied to the trolley is 7.50 N.

Step-by-step explanation:

To find the average force applied to the trolley, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In this case, the mass of the trolley is given as 0.250 kg and the time taken to reach the final speed is 0.200 s.

We can determine the acceleration of the trolley by using the equation for average acceleration, which is change in velocity divided by the time taken. The initial velocity is 0 m/s and the final velocity is given as 6.00 m/s, so the change in velocity is 6.00 m/s - 0 m/s = 6.00 m/s.

The average force applied to the trolley is then calculated as:

force = mass x acceleration = 0.250 kg x (6.00 m/s / 0.200 s) = 0.250 kg x 30.00 m/s^2 = 7.50 N