Question

Consider the neutralization reaction 2HNO₃ + Ba(OH)2 → 2H₂O + Ba(NO₃)2. What is the molarity of HNO₃ if 0.125 moles of Ba(OH)2 are required to neutralize 34.5 mL of HNO₃ solution?

1) 0.250 M
2) 0.500 M
3) 1.000 M
4) 2.000 M

Answer 1

To find the molarity of HNO₃, use the given balanced chemical equation and the given amount of Ba(OH)₂ to calculate the number of moles of HNO₃, and then divide the moles by the volume of the solution in liters.

This correct answer is none of the above.

Step-by-step explanation:

To find the molarity of HNO₃, we need to use the given balanced chemical equation and the given amount of Ba(OH)₂ to calculate the number of moles of HNO₃. Here are the steps:

1. Write the balanced chemical equation: 2HNO₃ + Ba(OH)₂ → 2H₂O + Ba(NO₃)₂

2. Use the mole ratio from the equation to find the number of moles of HNO₃:

0.125 moles Ba(OH)₂ x (2 moles HNO₃ / 1 mole Ba(OH)₂) = 0.250 moles HNO₃

3. Calculate the molarity of HNO₃:

Molarity = moles of solute / volume of solution in liters

Molarity = 0.250 moles HNO₃ / 0.0345 L = 7.25 M

So, the molarity of HNO₃ is 7.25 M.

This correct answer is none of the above.