Final answer:
The maximum number of stereoisomers for nootkatone is 4.
Step-by-step explanation:
The maximum number of stereoisomers for a compound with n number of chiral centers is given by the formula 2^n. In the case of nootkatone, we need to determine the number of chiral centers it has. A chiral center is a carbon atom bonded to four different atoms or groups. By examining the structure of nootkatone, we can identify that it has two chiral centers. Therefore, the maximum number of stereoisomers for nootkatone is 2^2 = 4 stereoisomers.