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Find the angle between the vectors a = 4i - 3j + k and b = 2i - k?

asked
User Mamed
by
9.3k points

1 Answer

4 votes

The angle between the vectors is 52.01 degrees

How to determine the angle between the vectors

From the question, we have the following parameters that can be used in our computation:

a = 4i - 3j + k and b = 2i - k

Where, we have

AB = (4i - 3j + k) * (2i - k)

Evaluate

AB = 8i.i - 3j.0 - k.k

This gives

AB = 8 - 0 - 1

AB = 7

Next, we have

|A| = √(4² + 3² + 1²) = 5.10

|B| = √(2² + 1²) = 2.23

The angle between them is then calculated as

cos(θ) = AB/{|A| * |B|)

This gives

cos(θ) = 7/(5.10 * 2.23)

cos(θ) = 0.6154

So, we have

θ = 52.01

Hence, the angle between the vectors is 52.01 degrees

answered
User Abhas
by
7.8k points

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