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The titration results shown that 25.0cm3 of 0.1m sodium hydroxide is needed to neutralized 21.0cm3 if hydrochloride acid 1calculate the concentration in moildm3 2calculate the concentration in gldm3 3what is the aims of the above

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To calculate the concentration of sodium hydroxide (NaOH), we use the formula: Concentration (mol/dm³) = moles/volume (dm³). From the given data, we calculate the concentration of NaOH to be 0.119 mol/dm³. The concentration of NaOH in g/dm³ can be calculated using the formula: Concentration (g/dm³) = concentration (mol/dm³) × molar mass (g/mol), resulting in a concentration of 4.76 g/dm³. The aim of the titration is to determine the concentration of NaOH by neutralizing it with a known volume and concentration of HCl.

1. To calculate the concentration of sodium hydroxide (NaOH) in mol/dm3, we can use the formula:

Concentration (mol/dm3) = moles/volume (dm3)

Since 25.0 cm3 of 0.1 M NaOH is needed to neutralize 21.0 cm3 of HCl, we can calculate the concentration of NaOH as follows:

Concentration (mol/dm3) = (0.1 mol/dm3 × 25.0 cm3) / (21.0 cm3) = 0.119 mol/dm3

2. To calculate the concentration of NaOH in g/dm3, we can use the formula:

Concentration (g/dm3) = concentration (mol/dm3) × molar mass (g/mol)

The molar mass of NaOH is 40.0 g/mol, so:

Concentration (g/dm3) = 0.119 mol/dm3 × 40.0 g/mol = 4.76 g/dm3

3. The aim of the above titration is to determine the concentration of sodium hydroxide (NaOH) by neutralizing it with a known volume and concentration of hydrochloric acid (HCl).

This allows us to calculate the moles and concentration of NaOH, which is useful in various applications such as determining the purity of NaOH or in chemical reactions where precise amounts of NaOH are required.

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