Question

A 8.52-L sample of gas has a pressure of 1.08 atm and a temperature of 91 °C. The sample is allowed to expand to a volume of 10.2 L and is heated to 150 °C. Calculate the new pressure of the gas, assuming that no gas escaped during the experiment.

Answer 1

Step-by-step explanation:

P1 V1 / T1 = P2V2/T2 T must be in Kelvin ( K = C° + 273.15)

1.08 * 8.52 / ( 91 + 273.15) = P2 * 10.2 / (150+273.15) Solve for P2

P2 = 1.048 atm