Question

An object is at rest on a surface with a coefficient of static friction of 0.60. The object has a mass of 350 kg. What the is the maximum value of static friction that is able to keep this object at rest?

Answer 1

The maximum value of static friction that is able to keep the object at rest is 2058 N.

Step-by-step explanation:

The maximum value of static friction that is able to keep the object at rest can be calculated using the formula:

Fs(max) = μs × FN

Where Fs(max) is the maximum static friction force,

μs is the coefficient of static friction, and

FN is the normal force.

The normal force can be calculated as:

FN = m × g

Where m is the mass of the object, and

g is the acceleration due to gravity.

Plugging in the given values, we have:

FN = 350 kg × 9.8 m/s2

= 3430 N

Fs(max) = 0.60 × 3430 N

= 2058 N

Therefore, the maximum value of static friction that is able to keep the object at rest is 2058 N.