Question

Four capacitors having values of 20μf, 50μf, 40μf, and 60μf are connected in parallel. What is the total capacitance of this circuit? Don't forget to give the proper units in your answer!

Answer 1

The total capacitance of four capacitors with values of 20μF, 50μF, 40μF, and 60μF connected in parallel is 170μF.

Step-by-step explanation:

The student has four capacitors with values of 20μF, 50μF, 40μF, and 60μF connected in parallel and wants to know the total capacitance of the circuit. In a parallel connection, the overall or total capacitance is simply the sum of all individual capacitances.

Using the formula for total capacitance in parallel: Cp = C1 + C2 + C3 + ..., where Cp is the total capacitance and C1, C2, C3, and so on are the capacitances of individual capacitors. For the given values, the total capacitance would be Cp = 20μF + 50μF + 40μF + 60μF.

So, the total capacitance of the circuit with these four capacitors connected in parallel is 170μF.