Final answer:
Doubling the frequency of light during the photoelectric effect increases the energy of each photon and therefore the kinetic energy of the ejected electrons, but it does not double the number of photons, their speed, or the number of electrons ejected per second which is related to the intensity of light. The Correct Answer is Option. A.
Step-by-step explanation:
When we discuss the photoelectric effect, we assess how light causes the ejection of electrons from a metal surface. According to Einstein's explanation, if we double the frequency of the light falling on a metal surface, we do not necessarily double the kinetic energy of ejected electrons, nor does it mean twice as many photons hit the surface. Instead, each photon now carries more energy (E = hv, where h is Planck's constant and v is frequency), which in turn increases the kinetic energy of the ejected electrons if the frequency is above the threshold frequency for that metal.
This is because the energy of the emitted electrons depends on the frequency of the light. However, neither the speed directly doubles nor is there a given that the number of photons or ejected electrons per second doubles. Doubling the frequency of the light affects the kinetic energy of the ejected electrons, but their quantity is related to the intensity (brightness) of light.