Question

HF(aq)+NaOH→NaF(aq)+H₂O(l) ΔH=−68.6 kJ/mol The high negative value of heat of reaction is due to:

A. In aqueous solution, HF is strong acid
B. Due to the high hydration energy of F⁻ ion
C. Heat of neutralisation of any strong acid with NaOH is −68.6 kJ mol⁻¹
D. HF is an associated liquid

Answer 1

The high negative value of the heat of reaction is due to the heat of neutralization between HF and NaOH. The correct answer is option C.

Step-by-step explanation:

The high negative value of heat of reaction is due to option C: Heat of neutralisation of any strong acid with NaOH is -68.6 kJ mol⁻¹.

When a strong acid, such as hydrofluoric acid (HF), reacts with a strong base, such as sodium hydroxide (NaOH), the reaction is highly exothermic, meaning that it releases a large amount of heat.

The heat of neutralization for the reaction between a strong acid and a strong base is typically around -57 to -58 kJ/mol.

The heat of neutralization for the reaction between HF and NaOH is even higher at -68.6 kJ/mol.

Therefore, the high negative value of the heat of reaction can be attributed to the heat of neutralization between HF and NaOH.