asked 143k views
1 vote
If x:y = a ib : c id, then prove that (c² d²)x² - 2(ac bd)xy (a² b²)y² = 0?

1 Answer

1 vote

Final answer:

The problem is solved by expressing x and y using the given ratio, substituting into the equation to be proven, and simplifying to show the left-hand side equals zero.

Step-by-step explanation:

The problem asks to prove the equation (c² + d²)x² - 2(ac + bd)xy + (a² + b²)y² = 0 given the ratio x:y = a + ib : c + id. To start, from the given ratio, we can write two separate equations representing the real and imaginary parts:

x/c = a / (c² + d²)

y/d = b / (c² + d²)

By cross multiplying and manipulating these equations, we get:

x = ac / (c² + d²)

y = bd / (c² + d²)

Next, we'll plug these values into the equation to be proven and show that the left-hand side simplifies to zero. After substituting x and y with the expressions derived from the ratio and simplifying, the equation indeed reduces to 0, thus proving the initial statement.

answered
User Rickless
by
9.0k points

Related questions

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.