Question

In the laboratory, a student adds 53.8 ml of water to 13.2 ml of a 0.665 m hydrobromic acid solution. what is the concentration of the diluted solution? assume the volumes are additive.

Answer 1

The concentration of the diluted solution is found using the formula M1V1 = M2V2, where M1 and V1 are the initial concentration and volume, and M2 and V2 are the final concentration and volume. Substituting the given values, the final volume of the solution is calculated to be 53.8 mL.

Step-by-step explanation:

To find the concentration of the diluted solution, we can use the formula:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

In this case, the initial concentration is 0.665 M, the initial volume is 13.2 mL, and the final concentration is unknown.

Solving for V2, the final volume, we get:

V2 = (M1V1) / M2 = (0.665 M x 13.2 mL) / (C M)

Substituting in the values, we have:

V2 = (0.665 M x 13.2 mL) / (C M) = 53.8 mL

Therefore, the final volume of the solution is 53.8 mL.