Question

Ainsley sells 8 times as many Volvos as Micah. If the difference

in their sales is 35, how many cars did Ainsley sell ?

Answer 1

Ainsley sold 40 cars. This was determined by setting up an equation where Ainsley sells 8 times as many cars as Micah with the difference in their sales being 35. Solving for Micah's sales first and using that to calculate Ainsley's sales.

Step-by-step explanation:

Let's denote the number of cars sold by Micah as M, then Ainsley sells 8 times that number, which is 8M. We are given that the difference in their sales is 35 cars. Therefore, we can describe the relationship between their sales in the following equation: 8M - M = 35.

To find out how many cars Ainsley sold, we first solve for M:

1. 8M - M = 7M
2. 7M = 35
3. M = 35 / 7
4. M = 5

Now we know Micah sold 5 cars, we can calculate Ainsley's sales:

1. Ainsley's sales = 8M
2. Ainsley's sales = 8 × 5
3. Ainsley's sales = 40

Therefore, Ainsley sold 40 cars.