Final answer:
The percent recombination between the A and B loci, based on the testcross Aa Bb × aa bb, which produced 10 Aa Bb, 40 Aa bb, 40 aa Bb, and 10 aa bb progeny, is 80%.
Step-by-step explanation:
The percent recombination between the A and B loci is calculated by adding the number of recombinant progeny and dividing by the total number of progeny, then multiplying by 100 to get the percentage. In this testcross, the recombinant progeny are the ones with genotypes different from both parents, which are Aa bb and aa Bb.
To find the percent recombination:
- First, add the number of recombinant progeny: 40 (Aa bb) + 40 (aa Bb) = 80.
- Next, calculate the total number of progeny by adding all the progeny groups together: 10 (Aa Bb) + 40 (Aa bb) + 40 (aa Bb) + 10 (aa bb) = 100.
- Finally, divide the number of recombinant progeny by the total number of progeny: 80/100 = 0.8.
- Multiply by 100 to convert to a percentage: 0.8 × 100 = 80%.
Therefore, the percent recombination between the A and B loci is 80%.