Final answer:
The angular speed of the bicycle wheel is 4π rad/s and the period of rotation, calculated using T = 2π/ω, is 0.5 seconds.
Step-by-step explanation:
The angular speed of a bicycle wheel is given as 4π rad/s.
The period of rotation is the time it takes for one complete rotation. Since the wheel has an angular speed of 4π rad/s, we use the formula for the period T = 2π/ω, where ω (omega) is the angular speed.
Plugging in the given value, we get T = 2π/(4π) = 0.5 s.
Therefore, the period of rotation is half a second.