Question

C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (l), ΔH = –2,220 kJ

For this equation, what is ΔH for 18 moles of CO2 ?
1. ΔH = –5,550 kJ
2. ΔH = - 39,960 kJ
3. ΔH = -13,320 kJ
4. ΔH = - 1492 kJ

Answer 1

The enthalpy change for 18 moles of CO₂ in the given reaction is approximately -5074 kJ.

Step-by-step explanation:

The enthalpy change for the conversion of 2 mol of CO to CO₂ is -566.0 kJ. To find the enthalpy change for 18 moles of CO₂, we can use the fact that the coefficient of CO₂ is 3. So, the enthalpy change for 1 mole of CO₂ is -566.0 ÷ 2 = -283.0 kJ/mol of CO.

Thus, the enthalpy change for 18 moles of CO₂ is -283.0 × 18 = -5074 kJ.