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Which equation results from isolating a radical term and squaring both sides of the equation for the equation √x+6+ √x=8?

a. X+6 = 64 - x
b. X+6 - 64+x
c. X+6 = 64+x-16 /
d. x+6 = 64+x+16V

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User Shaharg
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1 Answer

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Final answer:

To solve the given equation by isolating one radical and squaring both sides, it requires isolating \( \sqrt{x} \), squaring both sides, and then further manipulation to ultimately remove the radical.

Step-by-step explanation:

The equation \( \sqrt{x+6} + \sqrt{x} = 8 \) can be solved by isolating one of the radical terms and then squaring both sides of the equation. Isolating \( \sqrt{x} \) and squaring would give us:

\( (\sqrt{x+6} - \sqrt{x})^2 = (8 - \sqrt{x})^2 \)

Expanding both sides and simplifying would result in:

\( x+6 - 2\sqrt{x+6}\sqrt{x} + x = 64 - 16\sqrt{x} + x \).

As the equation contains a radical term \( \sqrt{x} \), further manipulation is needed to isolate and square the term again to remove the radical. This process can be extensive and requires careful simplification and the use of algebraic identities.