Question

PLS HELP!!!

When a rocker is launched it climbs 50 feet for every 13 feet it travels horizontally. Draw a diagram to represent the situation. Then estimate the rocket's launch angle.

Answer 1

453.9 that the answer

Answer 2

The rocket's launch angle is 75.42 degrees.

To estimate the launch angle, we need to find the angle between the vertical line and the diagonal trajectory line.

You can use a protractor or trigonometric functions to measure this angle.

Trigonometric approach:

We have the triangle ABC, where AB is the horizontal distance (13 ft), BC is the vertical climb (50 ft), and we need to find the angle ACB (launch angle).

tan(ACB) = BC / AB = 50 ft / 13 ft

take the inverse of the tangent value

= 75.42 degrees