Question

In a binomial situation, n = 6 and pi = 0.11. If x = 3, what is

the probability of this event? Round to 4 decimal places.

Answer 1

The probability of getting exactly 3 successes in a binomial situation with 6 trials and a success probability of 0.11 is approximately 0.0059 after applying the binomial probability formula.

Step-by-step explanation:

In the given binomial situation, we have n = 6 trials, and the probability of success in each trial, p, is 0.11. We want to find the probability that exactly x = 3 successes occur. The probability can be calculated using the binomial probability formula:

P(x) = (n choose x) * p^x * (1-p)^(n-x)

For x = 3, using the binomial probability formula, we get:

P(3) = (6 choose 3) * (0.11)^3 * (0.89)^3

P(3) = 20 * (0.11)^3 * (0.89)^3

P(3) ≈ 0.0059

This result is after calculating the bincomial probability function and rounding to four decimal places as instructed.