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Summerville has a population of 430,000 people, while Eagleton has a population of 5.7x10⁵. What is the difference in population between these two towns in scientific notation?

1 Answer

5 votes

Final answer:

To find the difference in population between Summerville and Eagleton, we subtract the population of Summerville from the population of Eagleton. The difference in population between Summerville and Eagleton in scientific notation is 1.4 × 105.

Step-by-step explanation:

The population of Summerville is 430,000 people, which can be represented in scientific notation as 4.3 × 105. The population of Eagleton is 5.7 × 105. To find the difference in population between the two towns, we subtract the population of Summerville from the population of Eagleton.

5.7 × 105 - 4.3 × 105 = (5.7 - 4.3) × 105 = 1.4 × 105

Therefore, the difference in population between Summerville and Eagleton in scientific notation is 1.4 × 105.

answered
User Mikko Paderes
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