Question

when tightening a bolt, you push perpendicularly on a wrench with a force of 258 n at a distance of 0.11 m from the center of the bolt. how much torque are you exerting (relative to the center of the bolt)?

Answer 1

Torque is the product of the force applied and the distance from the bolt. Applying a 258 N force at a distance of 0.11 m generates 28.38 N.m of torque, which converts to approximately 20.92 foot-pounds.

Step-by-step explanation:

The question asks how much torque is exerted when tightening a bolt while applying a force perpendicularly on a wrench. Torque (τ) is calculated using the formula τ = r × F × sin(θ),

where 'r' is the distance from the pivot point to the point where force is applied, 'F' is the applied force, and 'θ' is the angle between the force vector and the lever arm.

In this case, since the force is perpendicular to the wrench, 'θ' is 90 degrees, and the sine of 90 degrees is 1, simplifying our formula to τ = r × F.

For a force of 258 N applied at a distance of 0.11 m, the torque would be τ = 0.11 m × 258 N,

which calculates to τ = 28.38 N.m.

To convert this torque into foot-pounds, we use the conversion factor that 1 N.m is approximately equal to 0.73756 foot-pounds.

Therefore, τ in foot-pounds is approximately 28.38 N.m x 0.73756, which equals to about 20.92 foot-pounds.