Question

Find the height above the Earth that the Space Shuttle would be given:

Escape velocity (V) = 2.45 kilometers/second
Gravitational pull (g) = 0.0098 km/sec
Radius of the Earth (r) = 6440 km.

Answer 1

The height above the Earth that the Space Shuttle would be given the escape velocity V = 2.45 km/s, the gravitational pull g = 0.0098 km/sec, and the radius of the Earth r = 6440 km is approximately 1622.857 kilometers.

Step-by-step explanation:

The height above the Earth that the Space Shuttle would be given the escape velocity V = 2.45 kilometers/second, the gravitational pull g = 0.0098 km/sec, and the radius of the Earth r = 6440 km can be calculated using the formula:

h = (r^2 * g) / (2 * V^2)

Substituting the given values into the formula, h = (6440^2 * 0.0098) / (2 * 2.45^2) = 1622.857 km.

Therefore, the height above the Earth that the Space Shuttle would be is approximately 1622.857 kilometers.