Final answer:
The amount of heat transferred to lead when 355 grams are heated from 95°C to 140°C is 2537.55 Joules.
Step-by-step explanation:
To calculate the amount of heat transferred to lead, we can use the formula:
Q = m * c * ΔT
where Q is the heat transferred, m is the mass of the lead, c is the specific heat of lead, and ΔT is the change in temperature. Plugging in the values, we have:
Q = (355 g) * (0.129 J/g°C) * (140°C - 95°C)
Simplifying, we get:
Q = 2537.55 J
Therefore, the amount of heat transferred to lead when 355 grams are heated from 95°C to 140°C is 2537.55 Joules.