Question

How many moles of H2 are needed to make 6.30 moles of NH3?

OPTION 1: 3.15 moles
OPTION 2: 12.60 moles
OPTION 3: 9.45 moles
OPTION 4: 18.90 moles

Answer 1

Using the stoichiometric ratio from the balanced chemical equation N2 + 3 H2 → 2 NH3, we find that 9.45 moles of H2 are required to produce 6.30 moles of NH3.

Step-by-step explanation:

To determine how many moles of H2 are needed to make 6.30 moles of NH3, we need to refer to the balanced chemical equation for the formation of ammonia from nitrogen and hydrogen, which is:

N2 + 3 H2 → 2 NH3

From the equation, we see there is a stoichiometric ratio of 3 moles of hydrogen (H2) needed for every 2 moles of ammonia (NH3) produced. Therefore, we can set up a proportion to find how many moles of H2 are required for 6.30 moles of NH3:

(3 moles H2 / 2 moles NH3) x 6.30 moles NH3 = 9.45 moles H2

The correct answer is 9.45 moles of H2, which corresponds to OPTION 3.