asked 166k views
4 votes
A hollow, conducting sphere with an outer radius of 0.250 m and an inner radius of 0.160 m had a uniform surface charge density

of 5.870 nC/m². A charge of -0.5200 nC
is now introduced into the cavity inside the sphere.
What is the strength of the Electric Field just outside the conducting shell?

asked
User Agne
by
8.0k points

1 Answer

5 votes

Final answer:

The electric field just outside a conducting shell is zero due to the rearrangement of charges on the inner surface of the shell.

Step-by-step explanation:

The electric field just outside a conducting shell is zero. This is because the charges on the inner surface of the shell rearrange in response to the presence of the charge in the cavity, creating an opposite electric field that cancels out the electric field of the cavity charge. Therefore, the strength of the electric field just outside the conducting shell is zero.

answered
User Triby
by
8.8k points
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