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At a frequency of 8.69 x 10¹⁵ Hz, the energy of a photon is _________ joules?

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User Dobbo
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1 Answer

5 votes

Final answer:

The energy of a photon with a frequency of 8.69 x 10^15 Hz is 5.76 x 10^-18 joules, calculated using the equation E = hf, where h is Planck's constant and f is the frequency.

Step-by-step explanation:

The energy of a photon can be calculated using the equation E = hf, where E stands for energy, h is Planck's constant, and f is the frequency of the photon. Given that Planck's constant (h) is 6.626 x 10-34 J-s and the frequency (f) provided is 8.69 x 1015 Hz, you can find the energy of a photon by multiplying these two values.

Therefore, the energy (E) of the photon with a frequency of 8.69 x 1015 Hz is calculated as follows:

E = (6.626 x 10-34 J-s) x (8.69 x 1015 Hz) = 5.76 x 10-18 J.

answered
User Colm Troy
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8.2k points
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