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Which shows the linear equation y² = (1/6)(x - 12) written in standard form?

1) y = (1/6)x - 2
2) y = (1/6)x + 2
3) y = (1/6)x - 12
4) y = (1/6)x + 12

asked
User Jameela
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8.6k points

1 Answer

3 votes

Final answer:

The linear equation y² = (1/6)(x - 12) can be written in standard form as y = (1/6)x - 2.

Step-by-step explanation:

The linear equation y² = (1/6)(x - 12) can be written in standard form as y = (1/6)x - 2.

Here's how to convert it:

  1. Start with the given equation: y² = (1/6)(x - 12)
  2. Take the square root of both sides to isolate y: y = ±√((1/6)(x - 12))
  3. Since y cannot be negative, we can ignore the negative square root
  4. Simplify the expression inside the square root: y = √((x - 12)/6)
  5. Multiply both the numerator and denominator by 6 to clear the fraction: y = (1/6)x - 2

answered
User Boris Burkov
by
8.7k points

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