Question

Solve the following system of linear equations:

-3 + 6y = -3
1 + 2y = -7
a) y = 0.5, y = -4
b) y = 1, y = -3
c) y = -1, y = 3
d) y = -0.5, y = 4

Answer 1

The system of equations has no solution. None of the option is true.

Explanation:

To solve the system of linear equations, we can use the substitution method or the elimination method.

Let's use the substitution method in this case.

Given equations:

-3 + 6y = -3

1 + 2y = -7

We'll solve equation 1 for y, and then substitute the value of y into equation 2.

Solving equation 1 for y:

-3 + 6y = -3

6y = 0

y = 0

Now, we substitute y = 0 into equation 2:

1 + 2(0) = -7

1 = -7

It's clear that these equations lead to a contradiction, as 1 cannot equal -7.

This means that the system of equations is inconsistent and has no solution.

Therefore, the system of equations has no solution.