Final answer:
The mass of oxygen formed from the decomposition of lead (II) oxide is determined by subtracting the mass of lead from the mass of the lead (II) oxide. The calculation yields that 8.0 g of oxygen is formed.
Step-by-step explanation:
The question pertains to the calculation of the mass of oxygen formed from the decomposition of lead (II) oxide. Since 111.6 g of lead (II) oxide decomposes to form 103.6 g of lead, we can determine the mass of oxygen by subtracting the mass of lead from the total mass of lead (II) oxide:
Mass of oxygen = Mass of lead (II) oxide - Mass of lead
Mass of oxygen = 111.6 g - 103.6 g
Mass of oxygen = 8.0 g
Therefore, 8.0 g of oxygen is formed during the decomposition.