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Suppose that 8% of all cars produced at Plant A have a certain defect, and 5\% of all cars produced at Plant B have this defect. A quality control manager takes separate random samples of 150 cars from each plant. The manager will then look at the difference (A - B) between the proportions of cars with the defect in each sample. What will be the shape of the sampling distribution of the difference in sample proportions, and why?

asked
User IsaacK
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2 Answers

3 votes

Answer: D

Not normal, because we expect fewer than 10 defective cars in Plant B.
.05*150=7.5

Step-by-step explanation: Khan Answer

answered
User Malachi
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7.9k points
5 votes

Answer:

The answer is "Choice d"

Explanation:

Please find the complete question in the attached file.

Faulty factory cars in a plant
A = 8\% \ of\ 150 \ = 12 > 10

Faulty factory cars in a plant
B = 5\% \ of \ 150 = 7.5 < 10

This condition of the normal distribution is not met so because the number of negative cars from plant B is less than 10, that's why the choice d is correct.

Suppose that 8% of all cars produced at Plant A have a certain defect, and 5\% of-example-1
answered
User Alaa Ali
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6.7k points

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