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In the reaction N2(g) + 3H2(g) ⇄ 2NH3(g), what is the value of K if [NH3] = 0.18; [N2] = 0.50; and [H2] = 0.41?

asked
User MrFlick
by
8.1k points

1 Answer

3 votes

Answer: 0.94

Step-by-step explanation:

The formula for K from this reaction is:
([NH3]^2)/([N2][H2]^3) = K

Based on the data: [NH3] = 0.18

[N2] = 0.50

[H2] = 0.41

We just plug in the numbers:


([NH3]^2)/([N2][H2]^3) = K


([0.18]^2)/([0.50][0.41]^3) = K


K = 0.94

Some background information:

The K formula is the product over reactants. If you have a solid or a liquid compound in your reaction, its value in the equation becomes 1. So you can simply ignore it while calculating the K. The coefficient in the reaction of the compounds becomes the exponents in your K constant formula. As demonstrated above.

answered
User Anters Bear
by
8.5k points
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