Question

Find four consecutive odd integers whoes sum is 128

Answer 1

Explanation:

let the smallest odd integer be x

followed be x+2, x+4, and x+6

(it is +2 as after every odd number, it will be an even number, so in order for it to be a odd number again, you must +2)

x+(x+2)+(x+4)+(x+6) = 128

4x+12 = 128

4x = 128-12

= 116

x = 29

x+2 = 29+2

= 31

x+4 = 29+4

= 33

x+6 = 29+6

= 35

the four numbers are, 29, 31, 33, and 35